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    Suppose f is defined and differentiable for every x>0, and f'(x)->0 as x ->infinity.

    Suppose f is defined and differentiable for every x>0, and f'(x)->0 as x ->infinity. Put g(x)=f(x+1)-f(x).? Prove that g(x)->0 as x-> infinity.
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    • &gtinfinity defined differentiable fx&gt0 suppose x&gt0
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