Last July, scientists announced that they'd discovered what they strongly believed to be the Higgs Boson—but quirks in the data suggested that might not be the case. Now, though, CERN has announced that the observed particle is "looking more and more like a Higgs boson." More »
At a seminar held at CERN today as a curtain raiser to the year's major particle physics conference, ICHEP2012 in Melbourne, the ATLAS and CMS experiments presented their latest preliminary results in the search for the long sought Higgs particle.
during the time interval [-3,5]? The velocity function is v(t) = t^2 - 5t + 6 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [-3,5].
Cathode Ray Tube (CRT) televisions may be more than on their way to chill with the dodo bird in the land of extinction, but that doesn't mean the DIY sect amongst us can't enjoy its reto goodness anyway. More »
...closest approach, etc.? A particle is traveling along the line (x-3) / 2 = (y+1) / (-2) = z-1. Write the equation of its path in the form r = r(subscript 0) + At. Find the distance of closest approach of the particle to the origin (that is, the distance from the orgin to the line). If t...
The new "Twin Paradox": What would happen if a particle at rest were entangled...
...with one traveling at c? Would they even be able to become entangled if the particle in motion were already traveling at c? Would the entanglement hold and if so, what would readings of the moving particle's...
...traveling with velocity v = (-4.00 m/s) i? Particle Collision Two A collision occurs between a 2.00 kg particle traveling with velocity v = (-4.00 m/s) i + (-5.00 m/s) j and a 4.00 kg particle traveling with velocity v = (5.20 m/s) i + (-3.00 m/s) j. The collision connects the two particles...
given by a a N a T N T r r? Suppose j ˆ t i ˆ r(t) = 2t + 2 r
is the position vector of a moving particle. Determine the
tangential and normal components of the acceleration at any t.
to? a uniform negative acceleration (a) for a total period of 20 sec whereby the particle reverts back to its original position (from where it had started).
1) find uniform negative acceleration (a)
2) find time during which particle travelled backwards
3) find velocity with which its lands finally
velocity of the particle is u and...? ... the acceleration is given by -k(2u-v) where v is the velocity of the particle at any instant and k is a postive constant.
Find the time taken for the particle to come to rest??
Quite confused, please show working, thanks!!!!!
distance traveled by the particle.? What is the distance the particle traveled during the time interval [-2,6].
Do I separate the integral into two integrals? And then add them for distance traveled?
Particle Physics has become my religion. Does anyone else believe that "god" is
in the subatomic interactions? I'm not just talking about Einsteinian physics, but post-Einsteinian quark-theory and the like. (For those not of the geek set) If we are not as solid as we think and we are...
Particle travels from t=0 to t=4 along curve:
x=(t^2)/2
y=(1/3)(2t+1)^1.5
0<or equal to t <or equal to 4
At what point (x,y) has the particle covered 1/2 the length of the curve?
please show all steps