"the limit as t goes to infiniti of [sin(-t)/t]"
Help!
Well, I have the answer, its 0. But I don't know how to get to that answer. I know sin(t)/t=1 but that doesn't help much here.
Hmm...that makes sense that it would equal -1 if sin(-t) always = -sin(t) so the answer my prof gave must be...