hours going downstream.? •A motorboat takes hours to travel going upstream. The return trip takes hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
•A motorboat takes 5 hours to travel 300 km going upstream. The return trip takes 2 hours...
...208 km, and 19.2 h to make...? .. the return trip downstream. assuming the ship's speed relative to the water is the same in both cases calculate the speed of the current in the Nile?
What is the rate of the boat in? A motorboat travels 558 km in 6 hours going upstream and 1016km in 8 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
how long would it take to stuff an elephant's ear with pancakes?
Upon selection of BA, I will give my usual response to this question (if anyone is interested) : x
Mississippi River? For that matter how did Native Americans move down **and up** the Mississippi? Or did they at all?
There are some (controversial) theories that even Viking explorers traveled up the Mississippi from the delta to the confluence of the Arkansas River around 900-1000 AD.
But...
A boat travels 30 miles upstream in 4 hours. The trip downstream takes 2.5 hours. Find the rate of the boat in still water.
Choices:
a-12 mph
b-10 mph
c-9.75 mph
d-7.5 mph
From basic physics, distance = rate * time. Set up two equations:
Upstream: rate = 10 - r, time = t + 1, distance = 24 miles
Downstream: rate = 10 + r, time = t, distance = 24 miles
24 = (10 - r) * (t + 1)
24 = (10 + r) * t
Solve the system by substitution:
(10+r) = 24 / t
r = (24/t) - 10
24...
If a boat has a speed of 10mph in still water, the current speed is given by r and the boat is to travel 24 miles up stream and back, also it takes the boat 1 hour longer to make the trip upstream.
The driver of a boat which moves at 10m/s in still water wishes to travel directly across a narrow straight in which the current flows at 5.0m/s. At what angle upstream should the driver head the boat? I know I'm supposed to divide 10 by 5, but I don't understand how to get the angle. Every...