Reply to thread

Message: <blockquote data-quote="asimpleman" data-source="post: 1519363" data-attributes="member: 134943">In other words, the freight train is 110 miles north of the station when the passenger train leaves. The passenger train is traveling 11 mph faster that than the freight train, how long will the passenger train take to make up the 110 mile traveling 11 miles per hour faster.That would be 10 hours, 10 hours x 66 mile per hour = 660 miles north of the station.Or.Df = distance freight train, Dp = distance passenger trainDf = 2 hours x 55 miles per hour + X hours x 55 mile per hoursDp = X hours x 66 miles per hour(when they meet)  Dp = Df (2 x 55 ) +   55  X =  66 X110 + 55 X = 66 X110 = 11 X10 = X10 hours after the passenger train leaves or 12 hours after the freight train leaves</blockquote>