A plane leaves airport A and travels 580 miles to airport B on a bearing of N34oE...?

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Pintobean1993

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A plane leaves airport A and travels 580 miles to airport B on a bearing of N34oE. The plane later leaves airport B and travels to airport C 400 miles away on a bearing of S74oE. Find the distance from airport A to airport C to the nearest tenth of a mile.

I'm having such a hard time drawing this picture out and solving it. Please help! :)
 
Draw a line pointing N then take an angle 34 degrees to the right of this line - that is the track from A to B
For B to C draw a line from B to the S then go 74 degrees to the E
By the cosine rule
AC^2 = 580^2 + 400^ - 2*580*400*cos(34+74)
AC = 799 .9 miles
 
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