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Home and Car Audio
A stereo system draws 2.4 A at 120 V. The audio output power is 50 W.?
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<blockquote data-quote="wjllope" data-source="post: 1490718" data-attributes="member: 471466"><p>P = I*V</p><p>P = 2.4A * 120V</p><p>P = 288 W</p><p></p><p>if the output power is 50W, the efficiency of the output is</p><p>50W/288W ~ 17%</p><p></p><p>how much power is lost to heat is not obvious. there are other sources of losses besides heat (the efficiency of the speakers themselves etc etc).</p><p>but i guess we're supposed to assume that all inefficiency goes into heat. if so, 288W-50W = 238W is lost to heat (?).</p><p></p><p>cheers</p></blockquote><p></p>
[QUOTE="wjllope, post: 1490718, member: 471466"] P = I*V P = 2.4A * 120V P = 288 W if the output power is 50W, the efficiency of the output is 50W/288W ~ 17% how much power is lost to heat is not obvious. there are other sources of losses besides heat (the efficiency of the speakers themselves etc etc). but i guess we're supposed to assume that all inefficiency goes into heat. if so, 288W-50W = 238W is lost to heat (?). cheers [/QUOTE]
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