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A student takes a 5 question multiple choice quiz with 4 choices for each question.?
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<blockquote data-quote="Joseph" data-source="post: 1974147" data-attributes="member: 214925"><p>First of all, you need to find out how many different arrangements or combinations of 4 correct answers exist. This is 5 C 4 = 5.</p><p>So the student can answer 4 correct questions in 5 different ways (each way corresponding to one of the 5 questions being answered wrong).</p><p>The student's chance of guessing the correct answer for any question is 25% (1 out of 4). The student's chance of guessing 4 correct answers is (0.25)^4 = 3.9 * 10 ^-3</p><p>Since these can occur in 5 different combinations, the required probability is 5* 3.9 * 10^-3 = 0.02 (roughly).</p><p>Hope that helped.</p></blockquote><p></p>
[QUOTE="Joseph, post: 1974147, member: 214925"] First of all, you need to find out how many different arrangements or combinations of 4 correct answers exist. This is 5 C 4 = 5. So the student can answer 4 correct questions in 5 different ways (each way corresponding to one of the 5 questions being answered wrong). The student's chance of guessing the correct answer for any question is 25% (1 out of 4). The student's chance of guessing 4 correct answers is (0.25)^4 = 3.9 * 10 ^-3 Since these can occur in 5 different combinations, the required probability is 5* 3.9 * 10^-3 = 0.02 (roughly). Hope that helped. [/QUOTE]
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