A sum P0 is invested at 12% interest compounded monthly. How soon will it double?

Peabody

New member
Use A = P(1+r)^n

Here A = 2P , r = 12/12 = 1% per month n = 12k

2P = P ( 1.01)^12k

2 = (1.01)^12k

Take logs of both sides

log 2 = 12k log 1.01

k = log 2 /12 log 1.01 = 5.8 years
 
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