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<blockquote data-quote="jamess" data-source="post: 2643931" data-attributes="member: 216015">The general laws of mathematics apply to most high-level programming languages, including C++, C#, Java, Perl, Python, etc.The easiest way to remember it is by this acronym: BIMDASB&nbsp; //brackets always have priority, and as such are calculated first. Brackets inside of brackets are then again of higher priority, and this can regress infinitely.I //indices; that is, powers, squares, square-roots, cubes, always have second priorityMD //multiplication and division. These are of the same priority, and are always calculated before addition and subtractionAS //addition and subtraction - these are the last to be calculatedIf there are two operands of equal priority in the same expression, they will usually be calculated left-to-right.E.g. 2^2 * (4 * 3 / 2) + 55= 4 * (12/2) + 55= 4 * 6 + 55= 24 + 55= 79&nbsp; &nbsp; &nbsp;&nbsp; For your two expressions:(1) x = y / (z) * 1.0e-3is equivelent to: x = (y/z)*(1.0e-3)(2) x = y/(z*1.0e-3)is equivelent to: x=<img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f44d.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt="(y)" title="Thumbs up&nbsp; &nbsp; (y)"&nbsp; data-smilie="22"data-shortname="(y)" /> / (z*(1.0e-3))</blockquote>

[QUOTE="jamess, post: 2643931, member: 216015"] The general laws of mathematics apply to most high-level programming languages, including C++, C#, Java, Perl, Python, etc. The easiest way to remember it is by this acronym: BIMDAS B //brackets always have priority, and as such are calculated first. Brackets inside of brackets are then again of higher priority, and this can regress infinitely. I //indices; that is, powers, squares, square-roots, cubes, always have second priority MD //multiplication and division. These are of the same priority, and are always calculated before addition and subtraction AS //addition and subtraction - these are the last to be calculated If there are two operands of equal priority in the same expression, they will usually be calculated left-to-right. E.g. 2^2 * (4 * 3 / 2) + 55 = 4 * (12/2) + 55 = 4 * 6 + 55 = 24 + 55 = 79 For your two expressions: (1) x = y / (z) * 1.0e-3 is equivelent to: x = (y/z)*(1.0e-3) (2) x = y/(z*1.0e-3) is equivelent to: x=(y) / (z*(1.0e-3)) [/QUOTE]

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