Dec 9, 2011 #1 M Matt Active member Joined May 12, 2008 Messages 2,155 Reaction score 0 Points 36 Okay so the original equation is ZnSO4(aq) + 2NH3(aq)? + 2H2O(l) Zn(OH)2 + (NH4)2SO4 Net ionic would be: Zn2+ + SO4^2- + 2NH3 + 2H2O Zn2+ 2OH- + 2NH4 + SO4^2- 2NH3 + 2H2O 2OH- + 2NH4 is this correct?
Okay so the original equation is ZnSO4(aq) + 2NH3(aq)? + 2H2O(l) Zn(OH)2 + (NH4)2SO4 Net ionic would be: Zn2+ + SO4^2- + 2NH3 + 2H2O Zn2+ 2OH- + 2NH4 + SO4^2- 2NH3 + 2H2O 2OH- + 2NH4 is this correct?