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<blockquote data-quote="brittle" data-source="post: 1669246" data-attributes="member: 413139">...is limit as n goes to infinit? y of 1/(n*ln<img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f44e.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt="(n)" title="Thumbs down&nbsp; &nbsp; (n)"&nbsp; data-smilie="23"data-shortname="(n)" />)I mean, the second one is 1/ln<img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f44e.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt="(n)" title="Thumbs down&nbsp; &nbsp; (n)"&nbsp; data-smilie="23"data-shortname="(n)" />I&#039;ll ask it differently. Is the limit as n approaches infinity of 1/(n*ln<img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f44e.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt="(n)" title="Thumbs down&nbsp; &nbsp; (n)"&nbsp; data-smilie="23"data-shortname="(n)" />) equal to 0? And is this because if you split it into two ( 1/n and 1/ln<img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f44e.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt="(n)" title="Thumbs down&nbsp; &nbsp; (n)"&nbsp; data-smilie="23"data-shortname="(n)" />) they approach 0, so you can just multiply them?</blockquote>

[QUOTE="brittle, post: 1669246, member: 413139"] ...is limit as n goes to infinit? y of 1/(n*ln(n)) I mean, the second one is 1/ln(n) I'll ask it differently. Is the limit as n approaches infinity of 1/(n*ln(n)) equal to 0? And is this because if you split it into two ( 1/n and 1/ln(n)) they approach 0, so you can just multiply them? [/QUOTE]

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