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Lifestyle
The Great Outdoors
Frequency/Speed (Boat A and B) QUESTION!?
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<blockquote data-quote="gp4rts" data-source="post: 2683429" data-attributes="member: 121012"><p>If there are no crests between the boats, then the boats are ½ wavelength apart (when one boat is at the peak, the other is at the trough), The total wavelength ? is then twice the distance between the boats</p><p></p><p>? = 2+4.1 = 8.2 m</p><p></p><p>If three complete cycles (peak-to-peak) takes 26.1 s, then the frequency of the wave is 3/26.1 - 0.115 cycle/sec so f = 0.115 Hz</p><p></p><p>c = ?*f = 8.2*0.115 = 0.943 m/s</p></blockquote><p></p>
[QUOTE="gp4rts, post: 2683429, member: 121012"] If there are no crests between the boats, then the boats are ½ wavelength apart (when one boat is at the peak, the other is at the trough), The total wavelength ? is then twice the distance between the boats ? = 2+4.1 = 8.2 m If three complete cycles (peak-to-peak) takes 26.1 s, then the frequency of the wave is 3/26.1 - 0.115 cycle/sec so f = 0.115 Hz c = ?*f = 8.2*0.115 = 0.943 m/s [/QUOTE]
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