help with a math riddle??? the first three numbers are 3 digits squared of the...

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september23grace

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...same base number, and the next? find the following 7 number sequence:

the first three numbers are 3 digits squared of the same base number, and the next four digits are a different(second) base number, that base number squared, and that base number(the second base number) cubed twice.

*there are 4 different possibilities
 
Is this EXACTLY the way the problem is asked?
If so, it's terribly confusing and horribly ungrammatical.

"The first three numbers are 3 digits squared of the same base number"
This makes no sense.
Are you saying the first 3 numbers are each 3-digit numbers that are squares of some unknown number? or 3-digit numbers that are squares of 2 random digits of the same number? or they are 1-digit each and the 3 digits together is a square?

Also, you ask to find a 7 NUMBER sequence.
The first part mentions the first 3 NUMBERS, but the second part mentions the next 4 DIGITS. So are we looking for a 7 NUMBER sequence or a 7 DIGIT sequence?


Here's a hint for second part for what it's worth, since I'm not sure I understand this question at all.
The only base number that gives 2-digit square and 2-digit cube is 4
4^2 = 16
4^3 = 64

Sorry, but the first part has me completely baffled.
 
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