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Message: <blockquote data-quote="gAytheist" data-source="post: 2727911" data-attributes="member: 913248">Sorry, but you are way off.First, log(1-x) ? log(1) - log(x)Remember this rule:log(a*b) = log(a) + log(b)You have log(1-x) + log(1+x) = log(c) where c is a constant [equal to 0,75 in this particular case]Using the rule I mentioned above you can write the left hand side as:log[(1-x)(1+x)] = log(c)expand what's in the square brackets to get:log(1 - x^2) = log(c)Now you have log's on both sides and if they are to be equal then their arguments have to be equal.  This means(1 - x^2) = cRewrite this as:x^2 - 1 + c = 0substitute 0,75 for c to getx^2 - 0,25 = 0You should recognize the form on the left as something you can easily factor.(x - 0,5)(x + 0,5) = 0so x = ± 0,5</blockquote>