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Predictions and Prophecies
In iWork Numbers, how can I figure the accuracy of a prediction?
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<blockquote data-quote="Kasey" data-source="post: 2198023" data-attributes="member: 208919"><p>I have two columns. (A) is a prediction and (B) is an actual. I need a formula for accuracy. Right now I calculate the difference (A)-(B)=C and then calculate accuracy =1-(C/B) This works fine unless the prediction is lower than the actual in which case the accuracy % is given as more than 100%.</p><p></p><p>For example if the prediction is 14.5 and the actual is 15.15, the accuracy computes as 104.29%. I understand that I can subtract that number from 200 to get 95.71 - the correct accuracy. My question is how do I put all of that into one equation for a global formula for accuracy? I don't want to have to go back and switch formulas on a case by case basis depending on the prediction being over or under the actual.</p></blockquote><p></p>
[QUOTE="Kasey, post: 2198023, member: 208919"] I have two columns. (A) is a prediction and (B) is an actual. I need a formula for accuracy. Right now I calculate the difference (A)-(B)=C and then calculate accuracy =1-(C/B) This works fine unless the prediction is lower than the actual in which case the accuracy % is given as more than 100%. For example if the prediction is 14.5 and the actual is 15.15, the accuracy computes as 104.29%. I understand that I can subtract that number from 200 to get 95.71 - the correct accuracy. My question is how do I put all of that into one equation for a global formula for accuracy? I don't want to have to go back and switch formulas on a case by case basis depending on the prediction being over or under the actual. [/QUOTE]
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