Jun 16, 2025
Оfftopic Community
Оfftopic Community
Forums
New posts
Search forums
What's new
Featured content
New posts
New media
New media comments
New resources
New profile posts
Latest activity
Media
New media
New comments
Search media
Resources
Latest reviews
Search resources
Members
Current visitors
New profile posts
Search profile posts
Log in
Register
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
OffTopic Community
Random Interesting Topics
Interesting Vector Calculus problem?
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="jcoltea" data-source="post: 2002283" data-attributes="member: 726431"><p>Hello all! Our teacher gave us a difficult extra credit problem for our vector calculus class a few days ago, and I have been playing with it ever since but I can't seem to find the proper proof. Any help would be appreciated!</p><p></p><p>Suppose that the function F:[a.b] -->R^3 is a function that parametrizes a curve C (this means that F(a) = F(b)). Suppose that P (in the set of R3) is a point not on the curve. If Q = F(to) is a point on C that is as close to P as possible, with a<to<b. Prove that the vectors PQ and F'(to) are perpendicular. (F'(to) is the derivative of F at to)</p></blockquote><p></p>
[QUOTE="jcoltea, post: 2002283, member: 726431"] Hello all! Our teacher gave us a difficult extra credit problem for our vector calculus class a few days ago, and I have been playing with it ever since but I can't seem to find the proper proof. Any help would be appreciated! Suppose that the function F:[a.b] -->R^3 is a function that parametrizes a curve C (this means that F(a) = F(b)). Suppose that P (in the set of R3) is a point not on the curve. If Q = F(to) is a point on C that is as close to P as possible, with a<to<b. Prove that the vectors PQ and F'(to) are perpendicular. (F'(to) is the derivative of F at to) [/QUOTE]
Insert quotes…
Name
Verification
Please enable JavaScript to continue.
Loading…
Post reply
Top