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iHav to Drive
Eastern Imports
Is it Right? Evaluate the limit, if it exists : lim x-->infinity (5^x-3x)/(e^x+5x^2)?
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<blockquote data-quote="BZNK" data-source="post: 1563368" data-attributes="member: 612517"><p><strong>Is it Right? Evaluate the limit, if it exists : lim x-->infinity (5^x-3x)/(e^x+5x^2)?</strong></p><p></p><p>Evaluate the limit, if it exists : lim x-->infinity (5^x-3x)/(e^x+5x^2)</p><p></p><p>lim x-->infinity (5^x-3x)/(e^x+5x^2) => Infinity/Infinity</p><p></p><p>Since it is infinity/infinity , we can use L'Hospital's rule.</p><p></p><p>So: </p><p>lim x-->infinity (5x*ln5-3)/(e^x+10x) => Infinity/Infinity</p><p></p><p>Since it is infinity/infinity , we can use L'Hospital's rule again.</p><p></p><p>So:</p><p>lim x-->infinity 5/(e^x-10) = 5/infinity = 0</p><p></p><p>I just need to know if I did any mistakes.. if so.. please correct me..</p><p></p><p>Thank You!</p></blockquote><p></p>
[QUOTE="BZNK, post: 1563368, member: 612517"] [b]Is it Right? Evaluate the limit, if it exists : lim x-->infinity (5^x-3x)/(e^x+5x^2)?[/b] Evaluate the limit, if it exists : lim x-->infinity (5^x-3x)/(e^x+5x^2) lim x-->infinity (5^x-3x)/(e^x+5x^2) => Infinity/Infinity Since it is infinity/infinity , we can use L'Hospital's rule. So: lim x-->infinity (5x*ln5-3)/(e^x+10x) => Infinity/Infinity Since it is infinity/infinity , we can use L'Hospital's rule again. So: lim x-->infinity 5/(e^x-10) = 5/infinity = 0 I just need to know if I did any mistakes.. if so.. please correct me.. Thank You! [/QUOTE]
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