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<blockquote data-quote="fenchurchthesane" data-source="post: 1501577" data-attributes="member: 593748">Okay, let&#039;s call them a,b,c,d,e,fa+f=c+dPossible pairs: 1 and 5, 2 and 4, or 2 and 7, 4 and 5, or 2 and 9, 4 and 7f=e-1Possible values for f: For the 1 and 5, 2 and 4 situation:Not 1, because 2 is either an end or a middle, as we just established.Not 4, because 5 is the same.Not 2 or 5, because 3 and 6 are not in the puzzle.But it could be be 2 and 7, 4 and 5!&nbsp; And f is...Not 2, 5, or 7, because 3, 6, and 8 are not in the puzzle.Not 4, because if 4 is f than 5 is a.So let&#039;s try 2 and 9, 4 and 7.&nbsp; F =Not 2, 9, or 7, because 3, 10, and 8 are not in this puzzle.So it must be 4!So e is 5!And a is 7!7 b c d 5 4You know from the 3rd condition that d is 1, because the second condition says f = e - 1.That is a shame, because it was previously determined that c and d are 2 and 9.Something is wrong here, or you said it wrong or something.Oh, wait, I just read the answer above me.&nbsp; He is right, it is a trick question, as they never said you had to use all the answers.&nbsp; What a cop-out.</blockquote>

[QUOTE="fenchurchthesane, post: 1501577, member: 593748"] Okay, let's call them a,b,c,d,e,f a+f=c+d Possible pairs: 1 and 5, 2 and 4, or 2 and 7, 4 and 5, or 2 and 9, 4 and 7 f=e-1 Possible values for f: For the 1 and 5, 2 and 4 situation: Not 1, because 2 is either an end or a middle, as we just established. Not 4, because 5 is the same. Not 2 or 5, because 3 and 6 are not in the puzzle. But it could be be 2 and 7, 4 and 5! And f is... Not 2, 5, or 7, because 3, 6, and 8 are not in the puzzle. Not 4, because if 4 is f than 5 is a. So let's try 2 and 9, 4 and 7. F = Not 2, 9, or 7, because 3, 10, and 8 are not in this puzzle. So it must be 4! So e is 5! And a is 7! 7 b c d 5 4 You know from the 3rd condition that d is 1, because the second condition says f = e - 1. That is a shame, because it was previously determined that c and d are 2 and 9. Something is wrong here, or you said it wrong or something. Oh, wait, I just read the answer above me. He is right, it is a trick question, as they never said you had to use all the answers. What a cop-out. [/QUOTE]

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