Mathematical Riddle Help?

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AvengedSevenfoldt

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Hey guys there is this math problem that i cant solve it says...

"at irvs cycle rental shop, irv rents all kinds of cycles: unicycles, tandem bikes, regular bikes,and even tricycles for little kids. he parks all the cycles in front of his shop with a helmet for each rider strapped to the cycles. this morning irv counted 57 helmets and 115 wheels parked in front of his store. he knows he has an equal number of unicycles and tandem bikes. he also knows that he has 32 regular bikes. how many unicycles, tandem bikes, and tricycles does irv have?"

unicycles _____________

tandem bikes__________
tricycles _____________



THANK YOU BEST ANSWER 10 PTS
 
32 regular bikes = 64 wheels
115-64 = 51 wheels remaining

57 helmets -32 regular bikes = 25 helmets (and bikes) remaining

unicycles=tandems
9 tricycles=27 wheels. 51-27 = 24 wheels remaining.
25 helmets - 9 helmets = 16 helmets remaining.
8 unicycles + 8 Tandems = 24 wheels, 16 helmets.

So,
Unicycles = 8
Tandems = 8
Tricycles = 9
Reg. bikes = 32
Wheels = 115
Helmets = 57
 
32 regular bikes = 64 wheels
115-64 = 51 wheels remaining

57 helmets -32 regular bikes = 25 helmets (and bikes) remaining

unicycles=tandems
9 tricycles=27 wheels. 51-27 = 24 wheels remaining.
25 helmets - 9 helmets = 16 helmets remaining.
8 unicycles + 8 Tandems = 24 wheels, 16 helmets.

So,
Unicycles = 8
Tandems = 8
Tricycles = 9
Reg. bikes = 32
Wheels = 115
Helmets = 57
 
the answer varies
unicycles 1-46
tandem bikes 1-22
tricycles 1-16
jus depends on the combination
 
the answer varies
unicycles 1-46
tandem bikes 1-22
tricycles 1-16
jus depends on the combination
 
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