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iHav to Drive
Trucks and SUV
motion problem? A truck starts from rest, etc.?
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<blockquote data-quote="NoushadBinJamal" data-source="post: 741706" data-attributes="member: 340962"><p>well,</p><p></p><p>good question..</p><p></p><p>you understand that the body moves under gravity.... ok?..</p><p></p><p>over a plane having friction = 0(theoretically)</p><p></p><p>distance travelled= 175m</p><p></p><p>gradient theta= tan-1(59.1/175)</p><p></p><p>theta=18.66 degree</p><p></p><p>now </p><p></p><p>friction =0</p><p></p><p>as the body moves </p><p></p><p>m*g*h* sin(theta)= 1/2 mv^2</p><p></p><p>g*h*sin(theta) = 1/2 v^2</p><p></p><p>g=accelaration due to gravity</p><p></p><p>h=59.1m</p><p>from this you can find final velocity 'v'</p><p></p><p>now for the time,</p><p></p><p>use general equation s= ut + 1/2 a t^2</p><p></p><p>v= u+ at</p><p></p><p>here u=0</p><p></p><p>so v/t = a</p><p></p><p>hence </p><p></p><p>you can calculate t=s/v</p><p></p><p>s=175 m</p></blockquote><p></p>
[QUOTE="NoushadBinJamal, post: 741706, member: 340962"] well, good question.. you understand that the body moves under gravity.... ok?.. over a plane having friction = 0(theoretically) distance travelled= 175m gradient theta= tan-1(59.1/175) theta=18.66 degree now friction =0 as the body moves m*g*h* sin(theta)= 1/2 mv^2 g*h*sin(theta) = 1/2 v^2 g=accelaration due to gravity h=59.1m from this you can find final velocity 'v' now for the time, use general equation s= ut + 1/2 a t^2 v= u+ at here u=0 so v/t = a hence you can calculate t=s/v s=175 m [/QUOTE]
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