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<blockquote data-quote="JoelKatz" data-source="post: 2549729" data-attributes="member: 232450">int operation (int x, int y, int (*functocall)(int,int))This means that &#039;operation&#039; is a function that returns an integer (that&#039;s the &#039;int operation (&#039; part). It takes as parameters two integers, called &#039;x&#039; and &#039;y&#039; (that&#039;s the &#039;int x, int y&#039; part), and a pointer to a function called &#039;functocall&#039; which returns an integer and takes two integers (that&#039;s the &#039;int (*functocall)(int,int)&#039; part).int (*minus)(int,int) = subtraction;This creates a pointer called &#039;minus&#039; (that&#039;s the &#039;*minus&#039; part). It points to a function takes two integers as parameters and returns one (that&#039;s the &#039;int&#039; and &#039;(int,int)&#039; parts). The pointer initially points to the function named &#039;subtraction&#039; (that&#039;s the &#039;=subtraction&#039; part).Hope that helps.</blockquote>

[QUOTE="JoelKatz, post: 2549729, member: 232450"] int operation (int x, int y, int (*functocall)(int,int)) This means that 'operation' is a function that returns an integer (that's the 'int operation (' part). It takes as parameters two integers, called 'x' and 'y' (that's the 'int x, int y' part), and a pointer to a function called 'functocall' which returns an integer and takes two integers (that's the 'int (*functocall)(int,int)' part). int (*minus)(int,int) = subtraction; This creates a pointer called 'minus' (that's the '*minus' part). It points to a function takes two integers as parameters and returns one (that's the 'int' and '(int,int)' parts). The pointer initially points to the function named 'subtraction' (that's the '=subtraction' part). Hope that helps. [/QUOTE]

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