S spoon737 New member Feb 7, 2009 #2 Do you mean lim(x->inf.) 0/x = 0? Then yes. Otherwise, it's undefined, as infinity isn't a real number, which means you can't just plug it in like that.
Do you mean lim(x->inf.) 0/x = 0? Then yes. Otherwise, it's undefined, as infinity isn't a real number, which means you can't just plug it in like that.