The velocity of a particle is given by: v(t) = t^2 - 3t + 2. Find the

[ashroksout]

distance traveled by the particle.? What is the distance the particle traveled during the time interval [-2,6].

Do I separate the integral into two integrals? And then add them for distance traveled?

 

[kristie]

You can, but its easier to just integrate and use [-2, 6] as your limits of integration

So:
d = (1/3)t^3 - (3/2)t^2 + 2t

d(6) = 30
d(-2) = -12.67

distance traveled = 30 - (-12.67) = 42.67