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Two cyclists start biking from a trail's start 3 hours apart. The second
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<blockquote data-quote="DonM1" data-source="post: 2227953" data-attributes="member: 397170"><p>You are solving for time T, and you know that the distances D are the same, as the two cyclists catch up with each other.</p><p></p><p>Distance = Speed * time</p><p></p><p>Cyclist 1: D = (6 miles / hr) * T hours</p><p></p><p>Cyclist 2: D = (10 miles / hr) * (T-3 hours) </p><p> (T is time elapsed, and this cyclist spend 3 hours doing nothing, so travel time is T-3 hours)</p><p></p><p>So, 6T = 10T - 30</p><p></p><p>or, 30 = 4T</p><p></p><p>So T (total time elapsed) = 7.5 hours. The faster cyclist only pedals or 7.5 - 3 hours, or 4.5 hours.</p><p></p><p>When the ast cylist catches up with the slow one, it is usually obligatory to shout "on your left!" or "share the road, you idiot!" <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f642.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":-)" title="Smile :-)" data-smilie="1"data-shortname=":-)" /> Make sure you put that part in your homework as well.</p><p></p><p>Have a nice day.</p></blockquote><p></p>
[QUOTE="DonM1, post: 2227953, member: 397170"] You are solving for time T, and you know that the distances D are the same, as the two cyclists catch up with each other. Distance = Speed * time Cyclist 1: D = (6 miles / hr) * T hours Cyclist 2: D = (10 miles / hr) * (T-3 hours) (T is time elapsed, and this cyclist spend 3 hours doing nothing, so travel time is T-3 hours) So, 6T = 10T - 30 or, 30 = 4T So T (total time elapsed) = 7.5 hours. The faster cyclist only pedals or 7.5 - 3 hours, or 4.5 hours. When the ast cylist catches up with the slow one, it is usually obligatory to shout "on your left!" or "share the road, you idiot!" :-) Make sure you put that part in your homework as well. Have a nice day. [/QUOTE]
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