What is the magnitude of the acceleration of the Jeep as it travels from B to C?

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VanN1

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A lot of unnecessary information in this question. If the Jeep is traveling 10 m/s around a curve of radius R, then the acceleration is just the centripetal acceleration

a = v^2 / R

Newton's Second Law states the F(net) = m a, so the friction force F(f) is

F(f) = m v^2 / R
 
A 1000-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep encounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south.
What is the magnitude of the acceleration of the Jeep as it travels from B to C?
What is the magnitude of the frictional force between the tires and the road as the Jeep negotiates the curve from B to C?
 
A lot of unnecessary information in this question. If the Jeep is traveling 10 m/s around a curve of radius R, then the acceleration is just the centripetal acceleration

a = v^2 / R

Newton's Second Law states the F(net) = m a, so the friction force F(f) is

F(f) = m v^2 / R
 
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