What what distance above Earth would a satellite have a period of 125 min? ?

Ally

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T = 125 min = 125(60) = 7500 s
R = 6.38E6 m
m = 5.97E24 kg
G = 6.673E-11

I tried using the equation T = 2(3.14)sqr.d^3/Gm, but my answer seems to be a thousand off every time.
 
mrw^2 = GmM/r^2

Leads to

w^2 r^3 = GM

(2pi /T) ^2 r^3 = GM

4pi^2 r^3 = GM T^2

r^3 = GM T^2 / 4pi^2

Work out r^3 then r.

Since r = radius R of Earth + height above urface,h

h = r - R

Good luck.
 
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