Which value of c makes (n3 + 3)2 = nc + 6n3 + 9 true?

Jeliddle78

New member
Start by expanding the brackets:

(n^3+3)^2 is the same as writing (n^3+3)(n^3+3), so this becomes n^6+3n^3+3n^3+9, so the original equation can be written as n^6+6n^3+9, so c must be equal to 6.

Sorry that I can't help with the second one
 
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