J Jessica Active member Nov 17, 2012 #1 6,5,1,&9 Please explain. Also can you help me simplify this ... w^-4 /2w
J Jeliddle78 New member Dec 12, 2012 #2 Start by expanding the brackets: (n^3+3)^2 is the same as writing (n^3+3)(n^3+3), so this becomes n^6+3n^3+3n^3+9, so the original equation can be written as n^6+6n^3+9, so c must be equal to 6. Sorry that I can't help with the second one
Start by expanding the brackets: (n^3+3)^2 is the same as writing (n^3+3)(n^3+3), so this becomes n^6+3n^3+3n^3+9, so the original equation can be written as n^6+6n^3+9, so c must be equal to 6. Sorry that I can't help with the second one