A 100kg satellite is in orbit at 24000km. How much energy will it take to...

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...move it to a geostationary orbit? I got 2.2x10^7 J...not sure bout that...
Data: G=6.67e-11
Mass of earth =6e24
 
TE = KE + PE = 1/2 mv^2 - GMm/r
Because mv^2/r = GMm/r^2 or mv^2 = Gmm/r or 1/2 mv^2/r = GMm/2r
TE = -1/2 GMm/r so the required energy, E is given by
E = (1/2)GMm[1/24000 - 1/36000]
=(0.5x6.67x10^-11x6x10^24x100)(12000)/(24000x36000)
= 5.558x10^9 J
 
TE = KE + PE = 1/2 mv^2 - GMm/r
Because mv^2/r = GMm/r^2 or mv^2 = Gmm/r or 1/2 mv^2/r = GMm/2r
TE = -1/2 GMm/r so the required energy, E is given by
E = (1/2)GMm[1/24000 - 1/36000]
=(0.5x6.67x10^-11x6x10^24x100)(12000)/(24000x36000)
= 5.558x10^9 J
 
TE = KE + PE = 1/2 mv^2 - GMm/r
Because mv^2/r = GMm/r^2 or mv^2 = Gmm/r or 1/2 mv^2/r = GMm/2r
TE = -1/2 GMm/r so the required energy, E is given by
E = (1/2)GMm[1/24000 - 1/36000]
=(0.5x6.67x10^-11x6x10^24x100)(12000)/(24000x36000)
= 5.558x10^9 J
 
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