Feb 8, 2011 #1 S Sakoya New member Joined Feb 8, 2011 Messages 0 Reaction score 0 Points 0 ...it reaches a speed of 26.0 m/s.? Then the truck travels for 40.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s. How long is the truck in motion?
...it reaches a speed of 26.0 m/s.? Then the truck travels for 40.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s. How long is the truck in motion?
Feb 9, 2011 #2 A Alan Member Joined May 15, 2008 Messages 266 Reaction score 0 Points 16 v=u+at [v-u]/a=t=26/2=13sec 13+40+5=58sec or 13+40+50=103sec or 1min 40sec depends on 5sec or 50sec brake
v=u+at [v-u]/a=t=26/2=13sec 13+40+5=58sec or 13+40+50=103sec or 1min 40sec depends on 5sec or 50sec brake