S Seth Member Jul 1, 2013 #2 Call the base b and exponentiate each side of the equation base b (take b to the power of each side). This is the inverse of the log base b, so they cancel out. This gives: 7^ 1/3 = b^ 2/3 = (b²)^ 1/3 b² = 7 b = ?7
Call the base b and exponentiate each side of the equation base b (take b to the power of each side). This is the inverse of the log base b, so they cancel out. This gives: 7^ 1/3 = b^ 2/3 = (b²)^ 1/3 b² = 7 b = ?7
M mizoo New member Jul 3, 2013 #3 log (base b) (cube roof of 7) = 2/3 log (base b) 7^(1/3) = 2/3 b^(2/3) = 7^(1/3) (b^(2/3))^(3/2) = (7^(1/3))^(3/2) b = 7^(1/2) b = ?7
log (base b) (cube roof of 7) = 2/3 log (base b) 7^(1/3) = 2/3 b^(2/3) = 7^(1/3) (b^(2/3))^(3/2) = (7^(1/3))^(3/2) b = 7^(1/2) b = ?7