Hey, my teacher gave us this question and he gave us the answer but I can't for the life of me figure out how he came to it. Here is the question:
Four candidates are running for Mayor of Fernville. If A is twice as likely to win as B [that is P(A) = 2P(B)], B is two-thirds as likely as C to win, and C is one and a half times as likely to win as D, what are the probabilities that (a) A Wins and (b) C does not win.
[Hint: Express all probabilities in terms of P(D).]
Using that question he derived these probabilities:
P(A) = 4/11
P(B) = 2/11
P(C) = 3/11
P(D) = 2/11
Don't understand how he got those probabilities. Can anyone explain. Once I understand how he derived that the rest of the question should be a piece of cake.
Question answered. Thank you so much.
Four candidates are running for Mayor of Fernville. If A is twice as likely to win as B [that is P(A) = 2P(B)], B is two-thirds as likely as C to win, and C is one and a half times as likely to win as D, what are the probabilities that (a) A Wins and (b) C does not win.
[Hint: Express all probabilities in terms of P(D).]
Using that question he derived these probabilities:
P(A) = 4/11
P(B) = 2/11
P(C) = 3/11
P(D) = 2/11
Don't understand how he got those probabilities. Can anyone explain. Once I understand how he derived that the rest of the question should be a piece of cake.
Question answered. Thank you so much.