Aug 4, 2012 #1 S solar New member Joined Jul 21, 2008 Messages 11 Reaction score 0 Points 1 Please can you explain step by step beacsue I am not able to solve this particular problem.
Aug 4, 2012 #2 R RayS New member Joined Jun 27, 2008 Messages 12 Reaction score 0 Points 1 logx = m logy = n logx + logy = m + n added and log(xy) = m+n Used log rule ... logM + logN = logMN xy = 10 by definition of logarithm ... logu = v u = a where u=xy, a=10, and v=(m+n) .
logx = m logy = n logx + logy = m + n added and log(xy) = m+n Used log rule ... logM + logN = logMN xy = 10 by definition of logarithm ... logu = v u = a where u=xy, a=10, and v=(m+n) .
Aug 17, 2012 #3 M mathie New member Joined Aug 17, 2012 Messages 1 Reaction score 0 Points 1 Remember what log means. 10^m=x 10^n=y xy=10^m * 10^n=10^(m+n)
Oct 17, 2012 #4 C casey Member Joined May 12, 2008 Messages 381 Reaction score 0 Points 16 First, just for your own edification, it's log, not lg; anyway: We first write out the logarithms in a simple manner: log(x) = m log = n As we want to isolate x and y to multiply together, we raise both sides to 10^: 10^(log(x)) = 10^m 10^(log) = 10^n We can simplify from here: 10^log will cancel, leaving x or y: x = 10^m y = 10^n Now, we multiply these together: x*y = (10^m)*(10^n) x*y = 10^(m+n) There you go. Hope that helps.
First, just for your own edification, it's log, not lg; anyway: We first write out the logarithms in a simple manner: log(x) = m log = n As we want to isolate x and y to multiply together, we raise both sides to 10^: 10^(log(x)) = 10^m 10^(log) = 10^n We can simplify from here: 10^log will cancel, leaving x or y: x = 10^m y = 10^n Now, we multiply these together: x*y = (10^m)*(10^n) x*y = 10^(m+n) There you go. Hope that helps.