ok heres the question
15.6 g of aluminum hydroxide pellets are first dissolved in enough water to make 5 L of solution. Then 50 ml of this solution is place in a buret. If 18 ml of the aluminum hydroxide solution were required to neutralize .1 ml of the sulfuric acid solution, then what is the Molarity of the sulfuric acid?
I know the final answer is 10.8
and i know to start i need to convert grams to moles
after converting i got .2 mol Al(OH)2, but i dont know what to do from there
plz explain!
thanks, your help is greatly appreciated!
15.6 g of aluminum hydroxide pellets are first dissolved in enough water to make 5 L of solution. Then 50 ml of this solution is place in a buret. If 18 ml of the aluminum hydroxide solution were required to neutralize .1 ml of the sulfuric acid solution, then what is the Molarity of the sulfuric acid?
I know the final answer is 10.8
and i know to start i need to convert grams to moles
after converting i got .2 mol Al(OH)2, but i dont know what to do from there
plz explain!
thanks, your help is greatly appreciated!