Feb 24, 2009 #1 N NikNu New member Joined Feb 24, 2009 Messages 1 Reaction score 0 Points 1 I need working out as it is on a practice test
Feb 24, 2009 #2 R ruanchored New member Joined Feb 24, 2009 Messages 1 Reaction score 0 Points 1 To put the question into numbers: if 60% = 18.60, 100% = ?? .6x = 18.6 Solve for 'x': divide each side by .6 to isolate 'x': x = 18.6 / .6 x = 31 £31.00 Hope that's clear enough.
To put the question into numbers: if 60% = 18.60, 100% = ?? .6x = 18.6 Solve for 'x': divide each side by .6 to isolate 'x': x = 18.6 / .6 x = 31 £31.00 Hope that's clear enough.
Feb 24, 2009 #3 D Dev Member Joined Jun 10, 2008 Messages 56 Reaction score 0 Points 6 price with discount= £18.60 discount rate =60% therefore the original price is: =(£18.60 /60) * 100 =0.31 * 100 =£31.00 or in algebraic method:::: let say the original price is x discount rate is: 60% ==> 0.6 so: 0.6x = £18.60 x = £18.60 / 0.6 x = £31.00 therefore the original price is £31.00
price with discount= £18.60 discount rate =60% therefore the original price is: =(£18.60 /60) * 100 =0.31 * 100 =£31.00 or in algebraic method:::: let say the original price is x discount rate is: 60% ==> 0.6 so: 0.6x = £18.60 x = £18.60 / 0.6 x = £31.00 therefore the original price is £31.00
Feb 24, 2009 #4 W Workingman1 New member Joined Feb 24, 2009 Messages 2 Reaction score 0 Points 1 easy division. Take 18.6 and divide it by .4. You get 46.50