Feb 17, 2009 #1 L LeoL New member Joined Jun 6, 2008 Messages 16 Reaction score 0 Points 1 ...centered at 0 with radius of? convergence 1 which converges at both x=1 and x= -1. And another one which converges pointwise on (-1,1) but does not converge uniformly on (-1,1) Thank you!!!!!!!
...centered at 0 with radius of? convergence 1 which converges at both x=1 and x= -1. And another one which converges pointwise on (-1,1) but does not converge uniformly on (-1,1) Thank you!!!!!!!
Feb 17, 2009 #2 A AwmsA New member Joined Sep 8, 2008 Messages 10 Reaction score 0 Points 1 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
Feb 17, 2009 #3 A AwmsA New member Joined Sep 8, 2008 Messages 10 Reaction score 0 Points 1 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
Feb 17, 2009 #4 A AwmsA New member Joined Sep 8, 2008 Messages 10 Reaction score 0 Points 1 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
= cos(pi*n/2) / (n+1)