L LeoL New member Feb 17, 2009 #1 ...centered at 0 with radius of? convergence 1 which converges at both x=1 and x= -1. And another one which converges pointwise on (-1,1) but does not converge uniformly on (-1,1) Thank you!!!!!!!
...centered at 0 with radius of? convergence 1 which converges at both x=1 and x= -1. And another one which converges pointwise on (-1,1) but does not converge uniformly on (-1,1) Thank you!!!!!!!
A AwmsA New member Feb 17, 2009 #2 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
A AwmsA New member Feb 17, 2009 #3 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
A AwmsA New member Feb 17, 2009 #4 For the first, I believe C = cos(pi*n/2) / (n+1) will work For the second, C = 1 works.
= cos(pi*n/2) / (n+1)