If you have 85% inside the interval, then you'll have 15% outside the interval.
7.5% above
7.5% below
Find the z-score that corresponds to 0.075
(I'm using microsoft Excel to find this one, you can approximate it on a z-table)
z = -1.4395
so, basically, it will be 1.43 standard deviations above and below the mean that contains 85% of the data