Nov 29, 2009 #1 K Kat Member Joined May 11, 2008 Messages 703 Reaction score 0 Points 16 after one year, he has $4326.00 in the acct. how much did kevin originally invest. nearest penny
Nov 29, 2009 #2 N nozarnazari New member Joined Sep 1, 2008 Messages 9 Reaction score 0 Points 1 Investment[(1+0.05) x 1]=$4326.00 Investment=4326/1.05=$4120.00 God bless you.
Nov 29, 2009 #3 T Tensai New member Joined Nov 29, 2009 Messages 2 Reaction score 0 Points 1 4326-x = x*0.05*1 4326 = 0.05x + x 4326 = 1.05x x= 4120
Nov 30, 2009 #4 J JunAgruda New member Joined Sep 5, 2008 Messages 9 Reaction score 0 Points 1 Investment of Kevin—x: 0.05x = $4,326.00 - x 1.05x = $4,326.00 x = $4,120.00 Answer: $4,120.00 was the amount Kevin originally invested.
Investment of Kevin—x: 0.05x = $4,326.00 - x 1.05x = $4,326.00 x = $4,120.00 Answer: $4,120.00 was the amount Kevin originally invested.